Henri Lecoq
(1802-1871)

French botanist (1802-1871) – Henri Lecoq was born in Avesnes-sur-Helpe (Commune in Nord, France) on April 18th, 1802 and died in Clermont-Ferrand (Commune in Puy-de-Dôme, France) on August 4th, 1871 at the age of 69. Today Henri Lecoq would be 222 years old.

Age

how old was Henri Lecoq when he died?

69

Henri Lecoq died in 1871 at the age of 69.


Biographical data

Birthday April 18th, 1802 (Sunday)
Place of Birth Avesnes-sur-Helpe
Commune in Nord, France
Death Date August 4th, 1871 (Friday)
Death place Clermont-Ferrand
Commune in Puy-de-Dôme, France
Birth sign (Zodiac) Aries (The Ram) ♈
Chinese Zodiac Dog 狗

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Also born in 1802

Henri Lecoq

Birthday

When was Henri Lecoq born?

Henri Lecoq was born on April 18th, 1802.

Death

When did Henri Lecoq die?

Henri Lecoq died on August 4th, 1871 at the age of 69 in Clermont-Ferrand (Commune in Puy-de-Dôme, France). Today Henri Lecoq would be 222 years old.

Place of Birth

Where was Henri Lecoq born?

Avesnes-sur-Helpe (Commune in Nord, France).

Death place

Where did Henri Lecoq die?

Clermont-Ferrand (Commune in Puy-de-Dôme, France).

Zodiac

What is the zodiac sign of Henri Lecoq?

Henri Lecoq was born in the zodiac sign Aries (The Ram).

Chinese Zodiac

Which Chinese zodiac sign does Henri Lecoq have?

Henri Lecoq was born in 1802 in the year of the Chinese zodiac Dog.

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Died on August 4th, 1871:
Anniversaries of death

French botanist (1802-1871)

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