Horace Abbott
(1806-1887)

American iron manufacturer (1806-1887) – Horace Abbott was born in Sudbury (Town in Middlesex County, Massachusetts, United States) on July 29th, 1806 and died in Baltimore (City in Maryland, United States) on August 8th, 1887 at the age of 81. Today Horace Abbott would be 217 years old.

Age

how old was Horace Abbott when he died?

81

Horace Abbott died in 1887 at the age of 81.


Biographical data

Birthday July 29th, 1806 (Tuesday)
Place of Birth Sudbury
Town in Middlesex County, Massachusetts, United States
Death Date August 8th, 1887 (Monday)
Death place Baltimore
City in Maryland, United States
Birth sign (Zodiac) Leo (The Lion) ♌
Chinese Zodiac Tiger 兎

Other personalities born on July 29

Also born in 1806

Horace Abbott

Birthday

When was Horace Abbott born?

Horace Abbott was born on July 29th, 1806.

Death

When did Horace Abbott die?

Horace Abbott died on August 8th, 1887 at the age of 81 in Baltimore (City in Maryland, United States). Today Horace Abbott would be 217 years old.

Place of Birth

Where was Horace Abbott born?

Sudbury (Town in Middlesex County, Massachusetts, United States).

Death place

Where did Horace Abbott die?

Baltimore (City in Maryland, United States).

Zodiac

What is the zodiac sign of Horace Abbott?

Horace Abbott was born in the zodiac sign Leo (The Lion).

Chinese Zodiac

Which Chinese zodiac sign does Horace Abbott have?

Horace Abbott was born in 1806 in the year of the Chinese zodiac Tiger.

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Died on August 8th, 1887:
Anniversaries of death

American iron manufacturer (1806-1887)

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