James W. Abbott (75)
June 12th, 1948
American politician, South Dakota – James W. Abbott was born in Sioux City (City in Woodbury and Plymouth counties in northwestern Iowa, United States) on June 12th, 1948 and is 75 years old today.
Age
How old is James W. Abbott?
75
James W. Abbott is 75 years old.
Biographical data
| Birthday | June 12th, 1948 (Saturday) |
|---|---|
| Place of Birth | Sioux City City in Woodbury and Plymouth counties in northwestern Iowa, United States |
| Birth sign (Zodiac) | Gemini (The Twins) ♊ |
| Chinese Zodiac | Rat 鼠 |
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James W. Abbott
Birthday
When was James W. Abbott born?
James W. Abbott was born on June 12th, 1948.
Place of Birth
Where was James W. Abbott born?
Sioux City (City in Woodbury and Plymouth counties in northwestern Iowa, United States).
Zodiac
What is the zodiac sign of James W. Abbott?
James W. Abbott was born in the zodiac sign Gemini (The Twins).
Chinese Zodiac
Which Chinese zodiac sign does James W. Abbott have?
James W. Abbott was born in 1948 in the year of the Chinese zodiac Rat.
James W. Abbott: Future birthdays
Birthdays of famous people
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American politician, South Dakota
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75
