French physician (1786-1851) – Jean Guillaume Auguste Lugol was born in Montauban (Commune in Tarn-et-Garonne, France) on August 18th, 1786 and died in Neuilly-sur-Seine (Commune in Hauts-de-Seine, France) on September 16th, 1851 at the age of 65. Today Jean Guillaume Auguste Lugol would be 237 years old.
Jean Guillaume Auguste Lugol died in 1851 at the age of 65.
Birthday | August 18th, 1786 (Friday) |
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Place of Birth | Montauban Commune in Tarn-et-Garonne, France |
Death Date | September 16th, 1851 (Tuesday) |
Death place | Neuilly-sur-Seine Commune in Hauts-de-Seine, France |
Birth sign (Zodiac) | Leo (The Lion) ♌ |
Chinese Zodiac | Horse 馬 |
Jean Guillaume Auguste Lugol was born on August 18th, 1786.
Jean Guillaume Auguste Lugol died on September 16th, 1851 at the age of 65 in Neuilly-sur-Seine (Commune in Hauts-de-Seine, France). Today Jean Guillaume Auguste Lugol would be 237 years old.
Montauban (Commune in Tarn-et-Garonne, France).
Neuilly-sur-Seine (Commune in Hauts-de-Seine, France).
Jean Guillaume Auguste Lugol was born in the zodiac sign Leo (The Lion).
Jean Guillaume Auguste Lugol was born in 1786 in the year of the Chinese zodiac Horse.