Jean Lowry Rankin
(1795-1878)

American activist – Jean Lowry Rankin was born in Jonesborough (Town in Tennessee, United States) on December 1st, 1795 and died in on December 28th, 1878 at the age of 83. Today Jean Lowry Rankin would be 228 years old.

Age

how old was Jean Lowry Rankin when he died?

83

Jean Lowry Rankin died in 1878 at the age of 83.


Biographical data

Birthday December 1st, 1795 (Tuesday)
Place of Birth Jonesborough
Town in Tennessee, United States
Death Date December 28th, 1878 (Saturday)
Birth sign (Zodiac) Sagittarius (The Centaur/Archer) ♐
Chinese Zodiac Rabbit 兔

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Also born in 1795

Jean Lowry Rankin

Birthday

When was Jean Lowry Rankin born?

Jean Lowry Rankin was born on December 1st, 1795.

Death

When did Jean Lowry Rankin die?

Jean Lowry Rankin died on December 28th, 1878 at the age of 83 in . Today Jean Lowry Rankin would be 228 years old.

Place of Birth

Where was Jean Lowry Rankin born?

Jonesborough (Town in Tennessee, United States).

Zodiac

What is the zodiac sign of Jean Lowry Rankin?

Jean Lowry Rankin was born in the zodiac sign Sagittarius (The Centaur/Archer).

Chinese Zodiac

Which Chinese zodiac sign does Jean Lowry Rankin have?

Jean Lowry Rankin was born in 1795 in the year of the Chinese zodiac Rabbit.

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Died on December 28th, 1878:
Anniversaries of death

American activist

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