American lawyer and statesman, Virginia (1757-1837) – John Brown was born in Staunton (Independent city in Virginia, United States) on September 12th, 1757 and died in Lexington (City in and county seat of Fayette County, Kentucky, United States) on August 29th, 1837 at the age of 79. Today John Brown would be 266 years old.
John Brown died in 1837 at the age of 79.
Birthday | September 12th, 1757 (Monday) |
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Place of Birth | Staunton Independent city in Virginia, United States |
Death Date | August 29th, 1837 (Tuesday) |
Death place | Lexington City in and county seat of Fayette County, Kentucky, United States |
Birth sign (Zodiac) | Virgo (The Maiden) ♍ |
Chinese Zodiac | Ox 牛 |
John Brown was born on September 12th, 1757.
John Brown died on August 29th, 1837 at the age of 79 in Lexington (City in and county seat of Fayette County, Kentucky, United States). Today John Brown would be 266 years old.
Staunton (Independent city in Virginia, United States).
Lexington (City in and county seat of Fayette County, Kentucky, United States).
John Brown was born in the zodiac sign Virgo (The Maiden).
John Brown was born in 1757 in the year of the Chinese zodiac Ox.