John F. Shepard
(1881-1965)

American psychologist – John F. Shepard was born in Greenfield (City in Greene County, Illinois, United States) on January 30th, 1881 and died in on October 31st, 1965 at the age of 84. Today John F. Shepard would be 143 years old.

Age

how old was John F. Shepard when he died?

84

John F. Shepard died in 1965 at the age of 84.


Biographical data

Birthday January 30th, 1881 (Sunday)
Place of Birth Greenfield
City in Greene County, Illinois, United States
Death Date October 31st, 1965 (Sunday)
Birth sign (Zodiac) Aquarius (The Water-Bearer) ♒
Chinese Zodiac Snake 蛇

Other personalities born on January 30

Also born in 1881

John F. Shepard

Birthday

When was John F. Shepard born?

John F. Shepard was born on January 30th, 1881.

Death

When did John F. Shepard die?

John F. Shepard died on October 31st, 1965 at the age of 84 in . Today John F. Shepard would be 143 years old.

Place of Birth

Where was John F. Shepard born?

Greenfield (City in Greene County, Illinois, United States).

Zodiac

What is the zodiac sign of John F. Shepard?

John F. Shepard was born in the zodiac sign Aquarius (The Water-Bearer).

Chinese Zodiac

Which Chinese zodiac sign does John F. Shepard have?

John F. Shepard was born in 1881 in the year of the Chinese zodiac Snake.

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Died on October 31st, 1965:
Anniversaries of death

American psychologist

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