American politician, Missouri (1846-1898) – John Joseph O'Neill was born in St. Louis (Independent city in Missouri, United States) on June 25th, 1846 and died in St. Louis (Independent city in Missouri, United States) on February 19th, 1898 at the age of 51. Today John Joseph O'Neill would be 177 years old.
John Joseph O'Neill died in 1898 at the age of 51.
Birthday | June 25th, 1846 (Thursday) |
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Place of Birth | St. Louis Independent city in Missouri, United States |
Death Date | February 19th, 1898 (Saturday) |
Death place | St. Louis Independent city in Missouri, United States |
Birth sign (Zodiac) | Cancer (The Crab) ♋ |
Chinese Zodiac | Horse 馬 |
John Joseph O'Neill was born on June 25th, 1846.
John Joseph O'Neill died on February 19th, 1898 at the age of 51 in St. Louis (Independent city in Missouri, United States). Today John Joseph O'Neill would be 177 years old.
St. Louis (Independent city in Missouri, United States).
St. Louis (Independent city in Missouri, United States).
John Joseph O'Neill was born in the zodiac sign Cancer (The Crab).
John Joseph O'Neill was born in 1846 in the year of the Chinese zodiac Horse.