John Pope
(1822-1892)

Union United States Army general (1822-1892) – John Pope was born in Louisville (County seat of Jefferson County, Kentucky, United States) on March 16th, 1822 and died in Sandusky (City in Ohio, USA) on September 23rd, 1892 at the age of 70. Today John Pope would be 202 years old.

Age

how old was John Pope when he died?

70

John Pope died in 1892 at the age of 70.


Biographical data

Birthday March 16th, 1822 (Saturday)
Place of Birth Louisville
County seat of Jefferson County, Kentucky, United States
Death Date September 23rd, 1892 (Friday)
Death place Sandusky
City in Ohio, USA
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Horse 馬

Other personalities born on March 16

Also born in 1822

John Pope

Birthday

When was John Pope born?

John Pope was born on March 16th, 1822.

Death

When did John Pope die?

John Pope died on September 23rd, 1892 at the age of 70 in Sandusky (City in Ohio, USA). Today John Pope would be 202 years old.

Place of Birth

Where was John Pope born?

Louisville (County seat of Jefferson County, Kentucky, United States).

Death place

Where did John Pope die?

Sandusky (City in Ohio, USA).

Zodiac

What is the zodiac sign of John Pope?

John Pope was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does John Pope have?

John Pope was born in 1822 in the year of the Chinese zodiac Horse.

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Died on September 23rd, 1892:
Anniversaries of death

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Union United States Army general (1822-1892)