William Gamble
(1818-1866)

United States Army general – William Gamble was born in County Tyrone (County in Northern Ireland) on January 1st, 1818 and died in Nicaragua (Sovereign state in Central America) on December 20th, 1866 at the age of 48. Today William Gamble would be 206 years old.

Age

how old was William Gamble when he died?

48

William Gamble died in 1866 at the age of 48.


Biographical data

Birthday January 1st, 1818 (Thursday)
Place of Birth County Tyrone
County in Northern Ireland
Death Date December 20th, 1866 (Thursday)
Death place Nicaragua
Sovereign state in Central America
Birth sign (Zodiac) Capricorn (The Sea-Goat) ♑
Chinese Zodiac Tiger 兎

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Also born in 1818

William Gamble

Birthday

When was William Gamble born?

William Gamble was born on January 1st, 1818.

Death

When did William Gamble die?

William Gamble died on December 20th, 1866 at the age of 48 in Nicaragua (Sovereign state in Central America). Today William Gamble would be 206 years old.

Place of Birth

Where was William Gamble born?

County Tyrone (County in Northern Ireland).

Death place

Where did William Gamble die?

Nicaragua (Sovereign state in Central America).

Zodiac

What is the zodiac sign of William Gamble?

William Gamble was born in the zodiac sign Capricorn (The Sea-Goat).

Chinese Zodiac

Which Chinese zodiac sign does William Gamble have?

William Gamble was born in 1818 in the year of the Chinese zodiac Tiger.

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Died on December 20th, 1866:
Anniversaries of death

United States Army general

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