John Taylor
(1808-1887)

3rd President of the Church of Jesus Christ of Latter Day Saints – John Taylor was born in Milnthorpe (Town and civil parish in South Lakeland, Cumbria, UK) on November 1st, 1808 and died in Kaysville (City in Davis County, Utah, United States) on July 25th, 1887 at the age of 78. Today John Taylor would be 215 years old.

Age

how old was John Taylor when he died?

78

John Taylor died in 1887 at the age of 78.


Biographical data

Birthday November 1st, 1808 (Tuesday)
Place of Birth Milnthorpe
Town and civil parish in South Lakeland, Cumbria, UK
Death Date July 25th, 1887 (Monday)
Death place Kaysville
City in Davis County, Utah, United States
Birth sign (Zodiac) Scorpio (The Scorpion) ♏
Chinese Zodiac Dragon 龍

Other personalities born on November 1

Also born in 1808

John Taylor

Birthday

When was John Taylor born?

John Taylor was born on November 1st, 1808.

Death

When did John Taylor die?

John Taylor died on July 25th, 1887 at the age of 78 in Kaysville (City in Davis County, Utah, United States). Today John Taylor would be 215 years old.

Place of Birth

Where was John Taylor born?

Milnthorpe (Town and civil parish in South Lakeland, Cumbria, UK).

Death place

Where did John Taylor die?

Kaysville (City in Davis County, Utah, United States).

Zodiac

What is the zodiac sign of John Taylor?

John Taylor was born in the zodiac sign Scorpio (The Scorpion).

Chinese Zodiac

Which Chinese zodiac sign does John Taylor have?

John Taylor was born in 1808 in the year of the Chinese zodiac Dragon.

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Died on July 25th, 1887:
Anniversaries of death

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3rd President of the Church of Jesus Christ of Latter Day Saints