Josef Eisenkolb
(1821-1899)

Eisenkolb József, 1880
Eisenkolb József, 1880 Eisenkolb József, Josef Eisenkolb (1821–1899) magyarországi német tanár, zeneszerző, kántortanító Foto: Károly Divald / Public Domain

Josef Eisenkolb was born in Lovrin (Village in Timiș County, Romania) on September 8th, 1821 and died in Lovrin (Village in Timiș County, Romania) on April 1st, 1899 at the age of 77. Today Josef Eisenkolb would be 202 years old.

Age

how old was Josef Eisenkolb when he died?

77

Josef Eisenkolb died in 1899 at the age of 77.


Biographical data

Birthday September 8th, 1821 (Saturday)
Place of Birth Lovrin
Village in Timiș County, Romania
Death Date April 1st, 1899 (Saturday)
Death place Lovrin
Village in Timiș County, Romania
Birth sign (Zodiac) Virgo (The Maiden) ♍
Chinese Zodiac Snake 蛇

Other personalities born on September 8

Also born in 1821

Josef Eisenkolb

Birthday

When was Josef Eisenkolb born?

Josef Eisenkolb was born on September 8th, 1821.

Death

When did Josef Eisenkolb die?

Josef Eisenkolb died on April 1st, 1899 at the age of 77 in Lovrin (Village in Timiș County, Romania). Today Josef Eisenkolb would be 202 years old.

Place of Birth

Where was Josef Eisenkolb born?

Lovrin (Village in Timiș County, Romania).

Death place

Where did Josef Eisenkolb die?

Lovrin (Village in Timiș County, Romania).

Zodiac

What is the zodiac sign of Josef Eisenkolb?

Josef Eisenkolb was born in the zodiac sign Virgo (The Maiden).

Chinese Zodiac

Which Chinese zodiac sign does Josef Eisenkolb have?

Josef Eisenkolb was born in 1821 in the year of the Chinese zodiac Snake.

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Died on April 1st, 1899:
Anniversaries of death

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