Leopold Hennet
(1876-1950)

Austrian politician (1876-1950) – Leopold Hennet was born in Gaaden (Municipality in Mödling District, Lower Austria, Austria) on May 10th, 1876 and died in Vienna (Capital of and state in Austria) on March 27th, 1950 at the age of 73. Today Leopold Hennet would be 147 years old.

Age

how old was Leopold Hennet when he died?

73

Leopold Hennet died in 1950 at the age of 73.


Biographical data

Birthday May 10th, 1876 (Wednesday)
Place of Birth Gaaden
Municipality in Mödling District, Lower Austria, Austria
Death Date March 27th, 1950 (Monday)
Death place Vienna
Capital of and state in Austria
Birth sign (Zodiac) Taurus (The Bull) ♉
Chinese Zodiac Rat 鼠

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Leopold Hennet

Birthday

When was Leopold Hennet born?

Leopold Hennet was born on May 10th, 1876.

Death

When did Leopold Hennet die?

Leopold Hennet died on March 27th, 1950 at the age of 73 in Vienna (Capital of and state in Austria). Today Leopold Hennet would be 147 years old.

Place of Birth

Where was Leopold Hennet born?

Gaaden (Municipality in Mödling District, Lower Austria, Austria).

Death place

Where did Leopold Hennet die?

Vienna (Capital of and state in Austria).

Zodiac

What is the zodiac sign of Leopold Hennet?

Leopold Hennet was born in the zodiac sign Taurus (The Bull).

Chinese Zodiac

Which Chinese zodiac sign does Leopold Hennet have?

Leopold Hennet was born in 1876 in the year of the Chinese zodiac Rat.

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Died on March 27th, 1950:
Anniversaries of death

Austrian politician (1876-1950)

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