American explorer and naturalist – Mary Jobe Akeley was born in Ohio (State of the United States of America) on January 29th, 1878 and died in Stonington (Town in New London County, Connecticut, United States) on July 19th, 1966 at the age of 88. Today Mary Jobe Akeley would be 146 years old.
Mary Jobe Akeley died in 1966 at the age of 88.
Birthday | January 29th, 1878 (Tuesday) |
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Place of Birth | Ohio State of the United States of America |
Death Date | July 19th, 1966 (Tuesday) |
Death place | Stonington Town in New London County, Connecticut, United States |
Birth sign (Zodiac) | Aquarius (The Water-Bearer) ♒ |
Chinese Zodiac | Tiger 兎 |
Mary Jobe Akeley was born on January 29th, 1878.
Mary Jobe Akeley died on July 19th, 1966 at the age of 88 in Stonington (Town in New London County, Connecticut, United States). Today Mary Jobe Akeley would be 146 years old.
Ohio (State of the United States of America).
Stonington (Town in New London County, Connecticut, United States).
Mary Jobe Akeley was born in the zodiac sign Aquarius (The Water-Bearer).
Mary Jobe Akeley was born in 1878 in the year of the Chinese zodiac Tiger.