Sampson Avard
(1800-1869)

Mormon vigilante (1800-1869) – Sampson Avard was born in Saint Peter's (Parish) on October 23rd, 1800 and died in Edwardsville (City in Madison County, Illinois, United States) on April 15th, 1869 at the age of 68. Today Sampson Avard would be 223 years old.

Age

how old was Sampson Avard when he died?

68

Sampson Avard died in 1869 at the age of 68.


Biographical data

Birthday October 23rd, 1800 (Thursday)
Place of Birth Saint Peter's
Parish
Death Date April 15th, 1869 (Thursday)
Death place Edwardsville
City in Madison County, Illinois, United States
Birth sign (Zodiac) Libra (The Scales) ♎
Chinese Zodiac Monkey 猴

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Sampson Avard

Birthday

When was Sampson Avard born?

Sampson Avard was born on October 23rd, 1800.

Death

When did Sampson Avard die?

Sampson Avard died on April 15th, 1869 at the age of 68 in Edwardsville (City in Madison County, Illinois, United States). Today Sampson Avard would be 223 years old.

Place of Birth

Where was Sampson Avard born?

Saint Peter's (Parish).

Death place

Where did Sampson Avard die?

Edwardsville (City in Madison County, Illinois, United States).

Zodiac

What is the zodiac sign of Sampson Avard?

Sampson Avard was born in the zodiac sign Libra (The Scales).

Chinese Zodiac

Which Chinese zodiac sign does Sampson Avard have?

Sampson Avard was born in 1800 in the year of the Chinese zodiac Monkey.

Sampson Avard: Future birthdays

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Died on April 15th, 1869:
Anniversaries of death

Mormon vigilante (1800-1869)

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