Sanford I. Weill (91)
March 16th, 1933

American banker and philanthropist (born 1933) – Sanford I. Weill was born in Brooklyn (Borough of New York City, New York, United States) on March 16th, 1933 and is 91 years old today.

Age

How old is Sanford I. Weill?

91

Sanford I. Weill is 91 years old.


Biographical data

Birthday March 16th, 1933 (Thursday)
Place of Birth Brooklyn
Borough of New York City, New York, United States
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Rooster 雞

Other personalities born on March 16

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Sanford I. Weill

Birthday

When was Sanford I. Weill born?

Sanford I. Weill was born on March 16th, 1933.

Place of Birth

Where was Sanford I. Weill born?

Brooklyn (Borough of New York City, New York, United States).

Zodiac

What is the zodiac sign of Sanford I. Weill?

Sanford I. Weill was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does Sanford I. Weill have?

Sanford I. Weill was born in 1933 in the year of the Chinese zodiac Rooster.

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American banker and philanthropist (born 1933)