Théodore de Lameth
(1756-1854)

French soldier and politician (1756-1854) – Théodore de Lameth was born in Paris (Capital of France) on June 24th, 1756 and died in Pontoise (Commune in Val-d'Oise, France) on October 19th, 1854 at the age of 98. Today Théodore de Lameth would be 267 years old.

Age

how old was Théodore de Lameth when he died?

98

Théodore de Lameth died in 1854 at the age of 98.


Biographical data

Birthday June 24th, 1756 (Thursday)
Place of Birth Paris
Capital of France
Death Date October 19th, 1854 (Thursday)
Death place Pontoise
Commune in Val-d'Oise, France
Birth sign (Zodiac) Cancer (The Crab) ♋
Chinese Zodiac Rat 鼠

Other personalities born on June 24

Also born in 1756

Théodore de Lameth

Birthday

When was Théodore de Lameth born?

Théodore de Lameth was born on June 24th, 1756.

Death

When did Théodore de Lameth die?

Théodore de Lameth died on October 19th, 1854 at the age of 98 in Pontoise (Commune in Val-d'Oise, France). Today Théodore de Lameth would be 267 years old.

Place of Birth

Where was Théodore de Lameth born?

Paris (Capital of France).

Death place

Where did Théodore de Lameth die?

Pontoise (Commune in Val-d'Oise, France).

Zodiac

What is the zodiac sign of Théodore de Lameth?

Théodore de Lameth was born in the zodiac sign Cancer (The Crab).

Chinese Zodiac

Which Chinese zodiac sign does Théodore de Lameth have?

Théodore de Lameth was born in 1756 in the year of the Chinese zodiac Rat.

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Died on October 19th, 1854:
Anniversaries of death

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French soldier and politician (1756-1854)