Waite Hoyt
(1899-1984)

American baseball player – Waite Hoyt was born in Brooklyn (Borough of New York City, New York, United States) on September 9th, 1899 and died in Cincinnati (City in Ohio, United States; county seat of Hamilton County) on August 25th, 1984 at the age of 84. Today Waite Hoyt would be 124 years old.

Age

how old was Waite Hoyt when he died?

84

Waite Hoyt died in 1984 at the age of 84.


Biographical data

Birthday September 9th, 1899 (Saturday)
Place of Birth Brooklyn
Borough of New York City, New York, United States
Death Date August 25th, 1984 (Saturday)
Death place Cincinnati
City in Ohio, United States; county seat of Hamilton County
Birth sign (Zodiac) Virgo (The Maiden) ♍
Chinese Zodiac Pig 豬

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Waite Hoyt

Birthday

When was Waite Hoyt born?

Waite Hoyt was born on September 9th, 1899.

Death

When did Waite Hoyt die?

Waite Hoyt died on August 25th, 1984 at the age of 84 in Cincinnati (City in Ohio, United States; county seat of Hamilton County). Today Waite Hoyt would be 124 years old.

Place of Birth

Where was Waite Hoyt born?

Brooklyn (Borough of New York City, New York, United States).

Death place

Where did Waite Hoyt die?

Cincinnati (City in Ohio, United States; county seat of Hamilton County).

Zodiac

What is the zodiac sign of Waite Hoyt?

Waite Hoyt was born in the zodiac sign Virgo (The Maiden).

Chinese Zodiac

Which Chinese zodiac sign does Waite Hoyt have?

Waite Hoyt was born in 1899 in the year of the Chinese zodiac Pig.

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Died on August 25th, 1984:
Anniversaries of death

American baseball player

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