American politician (1742-1790) – William Hooper was born in Boston (Capital and largest city of Massachusetts, United States) on June 28th, 1742 and died in Hillsborough (Town in and county seat of Orange County, North Carolina, United States) on October 14th, 1790 at the age of 48. Today William Hooper would be 281 years old.
William Hooper died in 1790 at the age of 48.
Birthday | June 28th, 1742 (Thursday) |
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Place of Birth | Boston Capital and largest city of Massachusetts, United States |
Death Date | October 14th, 1790 (Thursday) |
Death place | Hillsborough Town in and county seat of Orange County, North Carolina, United States |
Birth sign (Zodiac) | Cancer (The Crab) ♋ |
Chinese Zodiac | Dog 狗 |
William Hooper was born on June 28th, 1742.
William Hooper died on October 14th, 1790 at the age of 48 in Hillsborough (Town in and county seat of Orange County, North Carolina, United States). Today William Hooper would be 281 years old.
Boston (Capital and largest city of Massachusetts, United States).
Hillsborough (Town in and county seat of Orange County, North Carolina, United States).
William Hooper was born in the zodiac sign Cancer (The Crab).
William Hooper was born in 1742 in the year of the Chinese zodiac Dog.