William Larrabee
(1832-1912)

American politician and teacher (1832-1912) – William Larrabee was born in Ledyard (Town in New London County, Connecticut, United States) on January 20th, 1832 and died in Clermont (City in Iowa) on November 16th, 1912 at the age of 80. Today William Larrabee would be 192 years old.

Age

how old was William Larrabee when he died?

80

William Larrabee died in 1912 at the age of 80.


Biographical data

Birthday January 20th, 1832 (Friday)
Place of Birth Ledyard
Town in New London County, Connecticut, United States
Death Date November 16th, 1912 (Saturday)
Death place Clermont
City in Iowa
Birth sign (Zodiac) Capricorn (The Sea-Goat) ♑
Chinese Zodiac Dragon 龍

Other personalities born on January 20

Also born in 1832

William Larrabee

Birthday

When was William Larrabee born?

William Larrabee was born on January 20th, 1832.

Death

When did William Larrabee die?

William Larrabee died on November 16th, 1912 at the age of 80 in Clermont (City in Iowa). Today William Larrabee would be 192 years old.

Place of Birth

Where was William Larrabee born?

Ledyard (Town in New London County, Connecticut, United States).

Death place

Where did William Larrabee die?

Clermont (City in Iowa).

Zodiac

What is the zodiac sign of William Larrabee?

William Larrabee was born in the zodiac sign Capricorn (The Sea-Goat).

Chinese Zodiac

Which Chinese zodiac sign does William Larrabee have?

William Larrabee was born in 1832 in the year of the Chinese zodiac Dragon.

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Died on November 16th, 1912:
Anniversaries of death

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American politician and teacher (1832-1912)