Ynez Seabury
(1907-1973)

American actress (1907-1973) – Ynez Seabury was born in Oregon (State of the United States of America) on June 26th, 1907 and died in Los Angeles (Largest city in California, United States of America) on April 11th, 1973 at the age of 65. Today Ynez Seabury would be 116 years old.

Age

how old was Ynez Seabury when he died?

65

Ynez Seabury died in 1973 at the age of 65.


Biographical data

Birthday June 26th, 1907 (Wednesday)
Place of Birth Oregon
State of the United States of America
Death Date April 11th, 1973 (Wednesday)
Death place Los Angeles
Largest city in California, United States of America
Birth sign (Zodiac) Cancer (The Crab) ♋
Chinese Zodiac Goat 羊

Other personalities born on June 26

Also born in 1907

Ynez Seabury

Birthday

When was Ynez Seabury born?

Ynez Seabury was born on June 26th, 1907.

Death

When did Ynez Seabury die?

Ynez Seabury died on April 11th, 1973 at the age of 65 in Los Angeles (Largest city in California, United States of America). Today Ynez Seabury would be 116 years old.

Place of Birth

Where was Ynez Seabury born?

Oregon (State of the United States of America).

Death place

Where did Ynez Seabury die?

Los Angeles (Largest city in California, United States of America).

Zodiac

What is the zodiac sign of Ynez Seabury?

Ynez Seabury was born in the zodiac sign Cancer (The Crab).

Chinese Zodiac

Which Chinese zodiac sign does Ynez Seabury have?

Ynez Seabury was born in 1907 in the year of the Chinese zodiac Goat.

Ynez Seabury: Future birthdays

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Died on April 11th, 1973:
Anniversaries of death

American actress (1907-1973)

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