American opera singer and philanthropist – Zelma Watson George was born in Hearne (City in Robertson County, Texas, United States) on December 8th, 1903 and died in Shaker Heights (City in Cuyahoga County, Ohio, United States) on July 3rd, 1994 at the age of 90. Today Zelma Watson George would be 120 years old.
Zelma Watson George died in 1994 at the age of 90.
Birthday | December 8th, 1903 (Tuesday) |
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Place of Birth | Hearne City in Robertson County, Texas, United States |
Death Date | July 3rd, 1994 (Sunday) |
Death place | Shaker Heights City in Cuyahoga County, Ohio, United States |
Birth sign (Zodiac) | Sagittarius (The Centaur/Archer) ♐ |
Chinese Zodiac | Rabbit 兔 |
Zelma Watson George was born on December 8th, 1903.
Zelma Watson George died on July 3rd, 1994 at the age of 90 in Shaker Heights (City in Cuyahoga County, Ohio, United States). Today Zelma Watson George would be 120 years old.
Hearne (City in Robertson County, Texas, United States).
Shaker Heights (City in Cuyahoga County, Ohio, United States).
Zelma Watson George was born in the zodiac sign Sagittarius (The Centaur/Archer).
Zelma Watson George was born in 1903 in the year of the Chinese zodiac Rabbit.