A. J. Slaughter (36)
August 3rd, 1987

American-Polish basketball player – A. J. Slaughter was born in Shelbyville (City in Shelby County, Kentucky, United States) on August 3rd, 1987 and is 36 years old today.

Age

How old is A. J. Slaughter?

36

A. J. Slaughter is 36 years old.


Biographical data

Birthday August 3rd, 1987 (Monday)
Place of Birth Shelbyville
City in Shelby County, Kentucky, United States
Birth sign (Zodiac) Leo (The Lion) ♌
Chinese Zodiac Rabbit 兔

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Also born in 1987

A. J. Slaughter

Birthday

When was A. J. Slaughter born?

A. J. Slaughter was born on August 3rd, 1987.

Place of Birth

Where was A. J. Slaughter born?

Shelbyville (City in Shelby County, Kentucky, United States).

Zodiac

What is the zodiac sign of A. J. Slaughter?

A. J. Slaughter was born in the zodiac sign Leo (The Lion).

Chinese Zodiac

Which Chinese zodiac sign does A. J. Slaughter have?

A. J. Slaughter was born in 1987 in the year of the Chinese zodiac Rabbit.

A. J. Slaughter: Future birthdays

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American-Polish basketball player

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