Alfred Holler
(1888-1954)

German painter and engraver (1888-1954) – Alfred Holler was born in Krefeld (City in North Rhine-Westphalia, Germany) on September 5th, 1888 and died in Eupen (City in the German-speaking Community of Belgium) on December 18th, 1954 at the age of 66. Today Alfred Holler would be 135 years old.

Age

how old was Alfred Holler when he died?

66

Alfred Holler died in 1954 at the age of 66.


Biographical data

Birthday September 5th, 1888 (Wednesday)
Place of Birth Krefeld
City in North Rhine-Westphalia, Germany
Death Date December 18th, 1954 (Saturday)
Death place Eupen
City in the German-speaking Community of Belgium
Birth sign (Zodiac) Virgo (The Maiden) ♍
Chinese Zodiac Rat 鼠

Other personalities born on September 5

Also born in 1888

Alfred Holler

Birthday

When was Alfred Holler born?

Alfred Holler was born on September 5th, 1888.

Death

When did Alfred Holler die?

Alfred Holler died on December 18th, 1954 at the age of 66 in Eupen (City in the German-speaking Community of Belgium). Today Alfred Holler would be 135 years old.

Place of Birth

Where was Alfred Holler born?

Krefeld (City in North Rhine-Westphalia, Germany).

Death place

Where did Alfred Holler die?

Eupen (City in the German-speaking Community of Belgium).

Zodiac

What is the zodiac sign of Alfred Holler?

Alfred Holler was born in the zodiac sign Virgo (The Maiden).

Chinese Zodiac

Which Chinese zodiac sign does Alfred Holler have?

Alfred Holler was born in 1888 in the year of the Chinese zodiac Rat.

Alfred Holler: Future birthdays

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Died on December 18th, 1954:
Anniversaries of death

German painter and engraver (1888-1954)

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