American physicist – Alfred Hubler was born in United States of America (Country primarily located in North America) on May 16th, 1957 and died in on January 27th, 2018 at the age of 60. Today Alfred Hubler would be 66 years old.
Alfred Hubler died in 2018 at the age of 60.
Birthday | May 16th, 1957 (Thursday) |
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Place of Birth | United States of America Country primarily located in North America |
Death Date | January 27th, 2018 (Saturday) |
Birth sign (Zodiac) | Taurus (The Bull) ♉ |
Chinese Zodiac | Rooster 雞 |
Alfred Hubler was born on May 16th, 1957.
Alfred Hubler died on January 27th, 2018 at the age of 60 in . Today Alfred Hubler would be 66 years old.
United States of America (Country primarily located in North America).
Alfred Hubler was born in the zodiac sign Taurus (The Bull).
Alfred Hubler was born in 1957 in the year of the Chinese zodiac Rooster.