Alfred J. Lotka
(1880-1949)

American mathematician – Alfred J. Lotka was born in Lviv (Capital city of Lviv Oblast in western Ukraine) on March 2nd, 1880 and died in New York City (Most populous city in the United States) on December 5th, 1949 at the age of 69. Today Alfred J. Lotka would be 144 years old.

Age

how old was Alfred J. Lotka when he died?

69

Alfred J. Lotka died in 1949 at the age of 69.


Biographical data

Birthday March 2nd, 1880 (Tuesday)
Place of Birth Lviv
Capital city of Lviv Oblast in western Ukraine
Death Date December 5th, 1949 (Monday)
Death place New York City
Most populous city in the United States
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Dragon 龍

Other personalities born on March 2

Also born in 1880

Alfred J. Lotka

Birthday

When was Alfred J. Lotka born?

Alfred J. Lotka was born on March 2nd, 1880.

Death

When did Alfred J. Lotka die?

Alfred J. Lotka died on December 5th, 1949 at the age of 69 in New York City (Most populous city in the United States). Today Alfred J. Lotka would be 144 years old.

Place of Birth

Where was Alfred J. Lotka born?

Lviv (Capital city of Lviv Oblast in western Ukraine).

Death place

Where did Alfred J. Lotka die?

New York City (Most populous city in the United States).

Zodiac

What is the zodiac sign of Alfred J. Lotka?

Alfred J. Lotka was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does Alfred J. Lotka have?

Alfred J. Lotka was born in 1880 in the year of the Chinese zodiac Dragon.

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Died on December 5th, 1949:
Anniversaries of death

American mathematician

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