Alfred L. Kroeber
(1876-1960)

American anthropologist – Alfred L. Kroeber was born in Hoboken (City in Hudson County, New Jersey, United States) on June 11th, 1876 and died in Paris (Capital of France) on October 5th, 1960 at the age of 84. Today Alfred L. Kroeber would be 147 years old.

Age

how old was Alfred L. Kroeber when he died?

84

Alfred L. Kroeber died in 1960 at the age of 84.


Biographical data

Birthday June 11th, 1876 (Sunday)
Place of Birth Hoboken
City in Hudson County, New Jersey, United States
Death Date October 5th, 1960 (Wednesday)
Death place Paris
Capital of France
Birth sign (Zodiac) Gemini (The Twins) ♊
Chinese Zodiac Rat 鼠

Other personalities born on June 11

Also born in 1876

Alfred L. Kroeber

Birthday

When was Alfred L. Kroeber born?

Alfred L. Kroeber was born on June 11th, 1876.

Death

When did Alfred L. Kroeber die?

Alfred L. Kroeber died on October 5th, 1960 at the age of 84 in Paris (Capital of France). Today Alfred L. Kroeber would be 147 years old.

Place of Birth

Where was Alfred L. Kroeber born?

Hoboken (City in Hudson County, New Jersey, United States).

Death place

Where did Alfred L. Kroeber die?

Paris (Capital of France).

Zodiac

What is the zodiac sign of Alfred L. Kroeber?

Alfred L. Kroeber was born in the zodiac sign Gemini (The Twins).

Chinese Zodiac

Which Chinese zodiac sign does Alfred L. Kroeber have?

Alfred L. Kroeber was born in 1876 in the year of the Chinese zodiac Rat.

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Died on October 5th, 1960:
Anniversaries of death

American anthropologist

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