Alfred Leo Abramowicz
(1919-1999)

American bishop (1919–1999) – Alfred Leo Abramowicz was born in Chicago (City and county seat of Cook County, Illinois, United States of America) on January 27th, 1919 and died in on September 12th, 1999 at the age of 80. Today Alfred Leo Abramowicz would be 105 years old.

Age

how old was Alfred Leo Abramowicz when he died?

80

Alfred Leo Abramowicz died in 1999 at the age of 80.


Biographical data

Birthday January 27th, 1919 (Monday)
Place of Birth Chicago
City and county seat of Cook County, Illinois, United States of America
Death Date September 12th, 1999 (Sunday)
Birth sign (Zodiac) Aquarius (The Water-Bearer) ♒
Chinese Zodiac Goat 羊

Other personalities born on January 27

Also born in 1919

Alfred Leo Abramowicz

Birthday

When was Alfred Leo Abramowicz born?

Alfred Leo Abramowicz was born on January 27th, 1919.

Death

When did Alfred Leo Abramowicz die?

Alfred Leo Abramowicz died on September 12th, 1999 at the age of 80 in . Today Alfred Leo Abramowicz would be 105 years old.

Place of Birth

Where was Alfred Leo Abramowicz born?

Chicago (City and county seat of Cook County, Illinois, United States of America).

Zodiac

What is the zodiac sign of Alfred Leo Abramowicz?

Alfred Leo Abramowicz was born in the zodiac sign Aquarius (The Water-Bearer).

Chinese Zodiac

Which Chinese zodiac sign does Alfred Leo Abramowicz have?

Alfred Leo Abramowicz was born in 1919 in the year of the Chinese zodiac Goat.

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Died on September 12th, 1999:
Anniversaries of death

American bishop (1919–1999)

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