Alfred Otto Schwede
(1915-1987)

German translator (1915-1987) – Alfred Otto Schwede was born in Haynsburg (Human settlement) on April 16th, 1915 and died in Hohen Neuendorf (Town in Brandenburg state, Germany) on August 7th, 1987 at the age of 72. Today Alfred Otto Schwede would be 109 years old.

Age

how old was Alfred Otto Schwede when he died?

72

Alfred Otto Schwede died in 1987 at the age of 72.


Biographical data

Birthday April 16th, 1915 (Friday)
Place of Birth Haynsburg
Human settlement
Death Date August 7th, 1987 (Friday)
Death place Hohen Neuendorf
Town in Brandenburg state, Germany
Birth sign (Zodiac) Aries (The Ram) ♈
Chinese Zodiac Rabbit 兔

Other personalities born on April 16

Also born in 1915

Alfred Otto Schwede

Birthday

When was Alfred Otto Schwede born?

Alfred Otto Schwede was born on April 16th, 1915.

Death

When did Alfred Otto Schwede die?

Alfred Otto Schwede died on August 7th, 1987 at the age of 72 in Hohen Neuendorf (Town in Brandenburg state, Germany). Today Alfred Otto Schwede would be 109 years old.

Place of Birth

Where was Alfred Otto Schwede born?

Haynsburg (Human settlement).

Death place

Where did Alfred Otto Schwede die?

Hohen Neuendorf (Town in Brandenburg state, Germany).

Zodiac

What is the zodiac sign of Alfred Otto Schwede?

Alfred Otto Schwede was born in the zodiac sign Aries (The Ram).

Chinese Zodiac

Which Chinese zodiac sign does Alfred Otto Schwede have?

Alfred Otto Schwede was born in 1915 in the year of the Chinese zodiac Rabbit.

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Died on August 7th, 1987:
Anniversaries of death

German translator (1915-1987)

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