American politician (1836-1909) – Alfred P. Swineford was born in Ashland (City in Ohio, United States) on September 14th, 1836 and died in Juneau (State capital of Alaska, United States) on October 26th, 1909 at the age of 73. Today Alfred P. Swineford would be 187 years old.
Alfred P. Swineford died in 1909 at the age of 73.
Birthday | September 14th, 1836 (Wednesday) |
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Place of Birth | Ashland City in Ohio, United States |
Death Date | October 26th, 1909 (Tuesday) |
Death place | Juneau State capital of Alaska, United States |
Birth sign (Zodiac) | Virgo (The Maiden) ♍ |
Chinese Zodiac | Monkey 猴 |
Alfred P. Swineford was born on September 14th, 1836.
Alfred P. Swineford died on October 26th, 1909 at the age of 73 in Juneau (State capital of Alaska, United States). Today Alfred P. Swineford would be 187 years old.
Ashland (City in Ohio, United States).
Juneau (State capital of Alaska, United States).
Alfred P. Swineford was born in the zodiac sign Virgo (The Maiden).
Alfred P. Swineford was born in 1836 in the year of the Chinese zodiac Monkey.