Alfred Wickenburg
(1885-1978)

Austrian painter (1885-1978) – Alfred Wickenburg was born in Bad Gleichenberg (Municipality in Südoststeiermark District, Styria, Austria) on July 26th, 1885 and died in Graz (Capital of Styria, Austria) on December 25th, 1978 at the age of 93. Today Alfred Wickenburg would be 138 years old.

Age

how old was Alfred Wickenburg when he died?

93

Alfred Wickenburg died in 1978 at the age of 93.


Biographical data

Birthday July 26th, 1885 (Sunday)
Place of Birth Bad Gleichenberg
Municipality in Südoststeiermark District, Styria, Austria
Death Date December 25th, 1978 (Monday)
Death place Graz
Capital of Styria, Austria
Birth sign (Zodiac) Leo (The Lion) ♌
Chinese Zodiac Rooster 雞

Other personalities born on July 26

Also born in 1885

Alfred Wickenburg

Birthday

When was Alfred Wickenburg born?

Alfred Wickenburg was born on July 26th, 1885.

Death

When did Alfred Wickenburg die?

Alfred Wickenburg died on December 25th, 1978 at the age of 93 in Graz (Capital of Styria, Austria). Today Alfred Wickenburg would be 138 years old.

Place of Birth

Where was Alfred Wickenburg born?

Bad Gleichenberg (Municipality in Südoststeiermark District, Styria, Austria).

Death place

Where did Alfred Wickenburg die?

Graz (Capital of Styria, Austria).

Zodiac

What is the zodiac sign of Alfred Wickenburg?

Alfred Wickenburg was born in the zodiac sign Leo (The Lion).

Chinese Zodiac

Which Chinese zodiac sign does Alfred Wickenburg have?

Alfred Wickenburg was born in 1885 in the year of the Chinese zodiac Rooster.

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Died on December 25th, 1978:
Anniversaries of death

Austrian painter (1885-1978)

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