Bobby Layne
(1926-1986)

American football player (1926–1986) – Bobby Layne was born in Coleman County (County in Texas, United States) on December 19th, 1926 and died in Lubbock (County seat of Lubbock County, Texas, United States) on December 1st, 1986 at the age of 59. Today Bobby Layne would be 97 years old.

Age

how old was Bobby Layne when he died?

59

Bobby Layne died in 1986 at the age of 59.


Biographical data

Birthday December 19th, 1926 (Sunday)
Place of Birth Coleman County
County in Texas, United States
Death Date December 1st, 1986 (Monday)
Death place Lubbock
County seat of Lubbock County, Texas, United States
Birth sign (Zodiac) Sagittarius (The Centaur/Archer) ♐
Chinese Zodiac Tiger 兎

Other personalities born on December 19

Also born in 1926

Bobby Layne

Birthday

When was Bobby Layne born?

Bobby Layne was born on December 19th, 1926.

Death

When did Bobby Layne die?

Bobby Layne died on December 1st, 1986 at the age of 59 in Lubbock (County seat of Lubbock County, Texas, United States). Today Bobby Layne would be 97 years old.

Place of Birth

Where was Bobby Layne born?

Coleman County (County in Texas, United States).

Death place

Where did Bobby Layne die?

Lubbock (County seat of Lubbock County, Texas, United States).

Zodiac

What is the zodiac sign of Bobby Layne?

Bobby Layne was born in the zodiac sign Sagittarius (The Centaur/Archer).

Chinese Zodiac

Which Chinese zodiac sign does Bobby Layne have?

Bobby Layne was born in 1926 in the year of the Chinese zodiac Tiger.

Bobby Layne: Future birthdays

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Died on December 1st, 1986:
Anniversaries of death

American football player (1926–1986)

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