French explorer – Henri Mouhot was born in Montbéliard (Commune in Doubs, France) on May 15th, 1826 and died in Luang Prabang (City located in north central Laos) on November 10th, 1861 at the age of 35. Today Henri Mouhot would be 197 years old.
Henri Mouhot died in 1861 at the age of 35.
Birthday | May 15th, 1826 (Monday) |
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Place of Birth | Montbéliard Commune in Doubs, France |
Death Date | November 10th, 1861 (Sunday) |
Death place | Luang Prabang City located in north central Laos |
Birth sign (Zodiac) | Taurus (The Bull) ♉ |
Chinese Zodiac | Dog 狗 |
Henri Mouhot was born on May 15th, 1826.
Henri Mouhot died on November 10th, 1861 at the age of 35 in Luang Prabang (City located in north central Laos). Today Henri Mouhot would be 197 years old.
Montbéliard (Commune in Doubs, France).
Luang Prabang (City located in north central Laos).
Henri Mouhot was born in the zodiac sign Taurus (The Bull).
Henri Mouhot was born in 1826 in the year of the Chinese zodiac Dog.