Horace Brown
(1898-1983)

American long-distance runner – Horace Brown was born in Morris County (County in New Jersey, United States) on March 30th, 1898 and died in Houston (City in Texas, United States) on December 25th, 1983 at the age of 85. Today Horace Brown would be 126 years old.

Age

how old was Horace Brown when he died?

85

Horace Brown died in 1983 at the age of 85.


Biographical data

Birthday March 30th, 1898 (Wednesday)
Place of Birth Morris County
County in New Jersey, United States
Death Date December 25th, 1983 (Sunday)
Death place Houston
City in Texas, United States
Birth sign (Zodiac) Aries (The Ram) ♈
Chinese Zodiac Dog 狗

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Also born in 1898

Horace Brown

Birthday

When was Horace Brown born?

Horace Brown was born on March 30th, 1898.

Death

When did Horace Brown die?

Horace Brown died on December 25th, 1983 at the age of 85 in Houston (City in Texas, United States). Today Horace Brown would be 126 years old.

Place of Birth

Where was Horace Brown born?

Morris County (County in New Jersey, United States).

Death place

Where did Horace Brown die?

Houston (City in Texas, United States).

Zodiac

What is the zodiac sign of Horace Brown?

Horace Brown was born in the zodiac sign Aries (The Ram).

Chinese Zodiac

Which Chinese zodiac sign does Horace Brown have?

Horace Brown was born in 1898 in the year of the Chinese zodiac Dog.

Horace Brown: Future birthdays

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Died on December 25th, 1983:
Anniversaries of death

American long-distance runner

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