German musician and composer (1747-1800) – Johann Abraham Peter Schulz was born in Lüneburg (Town and capital of the Lüneburg district in Lower Saxony, Germany) on March 31st, 1747 and died in Schwedt/Oder (Town in Brandenburg state, Germany) on June 10th, 1800 at the age of 53. Today Johann Abraham Peter Schulz would be 277 years old.
Johann Abraham Peter Schulz died in 1800 at the age of 53.
Birthday | March 31st, 1747 (Friday) |
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Place of Birth | Lüneburg Town and capital of the Lüneburg district in Lower Saxony, Germany |
Death Date | June 10th, 1800 (Tuesday) |
Death place | Schwedt/Oder Town in Brandenburg state, Germany |
Birth sign (Zodiac) | Aries (The Ram) ♈ |
Chinese Zodiac | Rabbit 兔 |
Johann Abraham Peter Schulz was born on March 31st, 1747.
Johann Abraham Peter Schulz died on June 10th, 1800 at the age of 53 in Schwedt/Oder (Town in Brandenburg state, Germany). Today Johann Abraham Peter Schulz would be 277 years old.
Lüneburg (Town and capital of the Lüneburg district in Lower Saxony, Germany).
Schwedt/Oder (Town in Brandenburg state, Germany).
Johann Abraham Peter Schulz was born in the zodiac sign Aries (The Ram).
Johann Abraham Peter Schulz was born in 1747 in the year of the Chinese zodiac Rabbit.