Ludovike Simanowiz
(1759-1827)

German painter (1759-1827) – Ludovike Simanowiz was born in Schorndorf (Town in Baden-Württemberg, Germany) on February 21st, 1759 and died in Ludwigsburg (City in Baden-Württemberg, Germany) on September 3rd, 1827 at the age of 68. Today Ludovike Simanowiz would be 265 years old.

Age

how old was Ludovike Simanowiz when he died?

68

Ludovike Simanowiz died in 1827 at the age of 68.


Biographical data

Birthday February 21st, 1759 (Wednesday)
Place of Birth Schorndorf
Town in Baden-Württemberg, Germany
Death Date September 3rd, 1827 (Monday)
Death place Ludwigsburg
City in Baden-Württemberg, Germany
Birth sign (Zodiac) Pisces (The Fish) ♓
Chinese Zodiac Rabbit 兔

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Ludovike Simanowiz

Birthday

When was Ludovike Simanowiz born?

Ludovike Simanowiz was born on February 21st, 1759.

Death

When did Ludovike Simanowiz die?

Ludovike Simanowiz died on September 3rd, 1827 at the age of 68 in Ludwigsburg (City in Baden-Württemberg, Germany). Today Ludovike Simanowiz would be 265 years old.

Place of Birth

Where was Ludovike Simanowiz born?

Schorndorf (Town in Baden-Württemberg, Germany).

Death place

Where did Ludovike Simanowiz die?

Ludwigsburg (City in Baden-Württemberg, Germany).

Zodiac

What is the zodiac sign of Ludovike Simanowiz?

Ludovike Simanowiz was born in the zodiac sign Pisces (The Fish).

Chinese Zodiac

Which Chinese zodiac sign does Ludovike Simanowiz have?

Ludovike Simanowiz was born in 1759 in the year of the Chinese zodiac Rabbit.

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Died on September 3rd, 1827:
Anniversaries of death

German painter (1759-1827)

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