American politician (1798-1859) – Mirabeau B. Lamar was born in Louisville (City in and the county seat of Jefferson County, Georgia, United States) on August 16th, 1798 and died in Richmond (City in Fort Bend County, Texas, United States) on December 19th, 1859 at the age of 61. Today Mirabeau B. Lamar would be 225 years old.
Mirabeau B. Lamar died in 1859 at the age of 61.
Birthday | August 16th, 1798 (Thursday) |
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Place of Birth | Louisville City in and the county seat of Jefferson County, Georgia, United States |
Death Date | December 19th, 1859 (Monday) |
Death place | Richmond City in Fort Bend County, Texas, United States |
Birth sign (Zodiac) | Leo (The Lion) ♌ |
Chinese Zodiac | Horse 馬 |
Mirabeau B. Lamar was born on August 16th, 1798.
Mirabeau B. Lamar died on December 19th, 1859 at the age of 61 in Richmond (City in Fort Bend County, Texas, United States). Today Mirabeau B. Lamar would be 225 years old.
Louisville (City in and the county seat of Jefferson County, Georgia, United States).
Richmond (City in Fort Bend County, Texas, United States).
Mirabeau B. Lamar was born in the zodiac sign Leo (The Lion).
Mirabeau B. Lamar was born in 1798 in the year of the Chinese zodiac Horse.