Aaron V. Brown
(1795-1859)

American politician (1795-1859) – Aaron V. Brown was born in Brunswick County (County in Virginia, United States) on August 15th, 1795 and died in Washington, D.C. (Capital city of the United States of America) on March 8th, 1859 at the age of 63. Today Aaron V. Brown would be 228 years old.

Age

how old was Aaron V. Brown when he died?

63

Aaron V. Brown died in 1859 at the age of 63.


Biographical data

Birthday August 15th, 1795 (Saturday)
Place of Birth Brunswick County
County in Virginia, United States
Death Date March 8th, 1859 (Tuesday)
Death place Washington, D.C.
Capital city of the United States of America
Birth sign (Zodiac) Leo (The Lion) ♌
Chinese Zodiac Rabbit 兔

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Aaron V. Brown

Birthday

When was Aaron V. Brown born?

Aaron V. Brown was born on August 15th, 1795.

Death

When did Aaron V. Brown die?

Aaron V. Brown died on March 8th, 1859 at the age of 63 in Washington, D.C. (Capital city of the United States of America). Today Aaron V. Brown would be 228 years old.

Place of Birth

Where was Aaron V. Brown born?

Brunswick County (County in Virginia, United States).

Death place

Where did Aaron V. Brown die?

Washington, D.C. (Capital city of the United States of America).

Zodiac

What is the zodiac sign of Aaron V. Brown?

Aaron V. Brown was born in the zodiac sign Leo (The Lion).

Chinese Zodiac

Which Chinese zodiac sign does Aaron V. Brown have?

Aaron V. Brown was born in 1795 in the year of the Chinese zodiac Rabbit.

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Died on March 8th, 1859:
Anniversaries of death

American politician (1795-1859)

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