Alexander H. Bailey
(1817-1874)

American politician – Alexander H. Bailey was born in Minisink (Township in New York) on August 14th, 1817 and died in Rome (City in Oneida County, New York, United States) on April 20th, 1874 at the age of 56. Today Alexander H. Bailey would be 206 years old.

Age

how old was Alexander H. Bailey when he died?

56

Alexander H. Bailey died in 1874 at the age of 56.


Biographical data

Birthday August 14th, 1817 (Thursday)
Place of Birth Minisink
Township in New York
Death Date April 20th, 1874 (Monday)
Death place Rome
City in Oneida County, New York, United States
Birth sign (Zodiac) Leo (The Lion) ♌
Chinese Zodiac Ox 牛

Other personalities born on August 14

Also born in 1817

Alexander H. Bailey

Birthday

When was Alexander H. Bailey born?

Alexander H. Bailey was born on August 14th, 1817.

Death

When did Alexander H. Bailey die?

Alexander H. Bailey died on April 20th, 1874 at the age of 56 in Rome (City in Oneida County, New York, United States). Today Alexander H. Bailey would be 206 years old.

Place of Birth

Where was Alexander H. Bailey born?

Minisink (Township in New York).

Death place

Where did Alexander H. Bailey die?

Rome (City in Oneida County, New York, United States).

Zodiac

What is the zodiac sign of Alexander H. Bailey?

Alexander H. Bailey was born in the zodiac sign Leo (The Lion).

Chinese Zodiac

Which Chinese zodiac sign does Alexander H. Bailey have?

Alexander H. Bailey was born in 1817 in the year of the Chinese zodiac Ox.

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Died on April 20th, 1874:
Anniversaries of death

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